I'm not going to actually multiply them out because that would take effort, and more stuff will cancel anyway. These numbers get big, but they cancel out the answer is (52♵1♵0♴9♴8)/(5♴♳♲♱) = 13♱7♵♴9♴8 when you cancel stuff out (I canceled a 4 from the 52, a 3 from the 51, and a 5 and a 2 from the 50). This is a little tough, but not actually that hard.įirst, you should know how many 5-card hands there are.
To view LaTeX on reddit, install one of the following: Articles must be accompanied by a comment designed to start discussion. Please read the submission and comment rules before posting. Submissions should state and outline problems or questions about a given field or link to an especially insightful article about a mathematical concept.
r/mathematics is a subreddit dedicated to focused questions and discussion concerning mathematics.